Random Loot Spawn - Printable Version

Random Loot Spawn - Printable Version

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+--- Thread: Random Loot Spawn (/showthread.php?tid=621386)

Random Loot Spawn - NealPeteros - 10.11.2016

How do I change the spawn of this loot

PHP код:



RLootObjects[0] = CreateObject(19054, -1956.1447, 287.1091, 35.4688,   87.72005, -23.87996, 0.00000);

to a random one. I made the random spawn float variable already. The problem is only here. This is how a player will receive the loot.

PHP код:



if (newkeys & KEY_NO)

    {

        if(IsValidObject(LootObjects[0]) && IsPlayerInRangeOfPoint(playerid,2.0,-1956.1447, 287.1091, 35.4688))

        {

            AddItem(playerid,"M4A1",1);

            SendClientMessage(playerid, COLOR_GREEN, "* 1 M4A1 has been added to your inventory");

            DestroyObject(LootObjects[0]);

        }

How do I change

Код:

if(IsValidObject(LootObjects[0]) && IsPlayerInRangeOfPoint(playerid,2.0,-1956.1447, 287.1091, 35.4688))

so that when the player is in range of the random loot spawn, he will get the M4A1. Cause I just cant use the random float spawn.

Sorry if I can't explain it well. I'm really confused on this that I don't even know how to explain it.

EDIT: DON'T MIND

Quote:

How do I change the spawn of this loot

PHP код:



RLootObjects[0] = CreateObject(19054, -1956.1447, 287.1091, 35.4688,   87.72005, -23.87996, 0.00000);

to a random one.

Re: Random Loot Spawn - NealPeteros - 10.11.2016

Tried my best to simplify it:

Something like this

PHP код:



IsPlayerInRangeOfPoint(playerid,2.0,LootObjects[0]);

but translated from my confusing language to PAWN language