getarg, setarg and numarg - Printable Version

getarg, setarg and numarg - Printable Version

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+--- Thread: getarg, setarg and numarg (/showthread.php?tid=618088)

getarg, setarg and numarg - NeXoR - 30.09.2016

Heya, I have to create a stock that will get the highest number of the entered numbers.
Now I realize why RP Gamemodes have a "not for beginners" note, since I started at a roleplay script without learning the basics.
Anyways, can anyone give me a small explanation of how to do it ?

Re: getarg, setarg and numarg - Kaliber - 30.09.2016

Just like this:

PHP Code:



//You cant name this max..cause this name is already used by samp

stock maxi(...)

{

    if(!numargs()) return 0; //To provide server crash!

    new m=getarg(0);

    for(new i = numargs()-1; i!=0; i--)

    {

        if(getarg(i) > m) m=getarg(i);

    }

    return m;

}

//Usage:

printf("%d",maxi(1,3,0,5,3,2,1,-1,4)); //returns 5

Re: getarg, setarg and numarg - NeXoR - 30.09.2016

Quote:

Originally Posted by Kaliber

Just like this:

PHP Code:



//You cant name this max..cause this name is already used by samp

stock maxi(...)

{

    if(!numargs()) return 0; //To provide server crash!

    new m=getarg(0);

    for(new i = numargs()-1; i!=0; i--)

    {

        if(getarg(i) > m) m=getarg(i);

    }

    return m;

}

//Usage:

printf("%d",maxi(1,3,0,5,3,2,1,-1,4)); //returns 5

Thank you very much, can you explain getarg() and numarg() in like a sentence or two ? so I can understand what it does

Re: getarg, setarg and numarg - Kaliber - 30.09.2016

For example you call this maxi(1,2,3)

numargs() will count the arguments you pass..in that case..they are 3..numarg() = 3

maxi() if you would call this, numarg() = 0

so and getarg(0) gets the first argument you pass..in that case...1..so:
getarg(0) = 1
getarg(1) = 2
getarg(2) = 3

aaand thats it

Re: getarg, setarg and numarg - NeXoR - 30.09.2016

Quote:

Originally Posted by Kaliber

For example you call this maxi(1,2,3)

numargs() will count the arguments you pass..in that case..they are 3..numarg() = 3

maxi() if you would call this, numarg() = 0

so and getarg(0) gets the first argument you pass..in that case...1..so:
getarg(0) = 1
getarg(1) = 2
getarg(2) = 3

aaand thats it

Thank you very much!
Last question, setarg ?

Re: getarg, setarg and numarg - Kaliber - 30.09.2016

As the function says...it sets the value of an argument..for example:

PHP Code:



stock setter(...)

{

    setarg(0,0,999);

}


//Usage:

new x=0;

setter(x);

//and now x=999

The usage:

PHP Code:



setarg(arg, index=0, value)

First the argument...in this case 0...cause we only pass 1 argument, and we know its always on the first place so 0.
The index of integer Values is always 0 (only for strings to go through an arrays it can be 0-sizeof(arr))
And last the value you wanna set

Re: getarg, setarg and numarg - NeXoR - 30.09.2016

Quote:

Originally Posted by Kaliber

As the function says...it sets the value of an argument..for example:

PHP Code:



stock setter(...)

{

    setarg(0,0,999);

}


//Usage:

new x=0;

setter(x);

//and now x=999

The usage:

PHP Code:



setarg(arg, index=0, value)

Thank you very much, would have repped you for the three comments but I'm limited to one

Last thing, on this:

PHP Code:



 for(new i = numargs() - 1; i!=0; i--)

Why -1 on the new i ?

Re: getarg, setarg and numarg - SickAttack - 30.09.2016

It's a function, not a stock.

--------------------------

Because "new m=getarg(0);"

Re: getarg, setarg and numarg - GoldenLion - 30.09.2016

Quote:

Originally Posted by SickAttack

It's a function, not a stock.

Yes! https://sampforum.blast.hk/showthread.php?tid=570635

Re: getarg, setarg and numarg - SickAttack - 30.09.2016

Quote:

Originally Posted by GoldenLion

Yes! https://sampforum.blast.hk/showthread.php?tid=570635

It's not a requirement. Anything with stock is left out of the compiled source.