Tag Mismatch - Printable Version

Tag Mismatch - Printable Version

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+--- Thread: Tag Mismatch (/showthread.php?tid=587370)

Tag Mismatch - nezo2001 - 30.08.2015

PHP код:



Cache:result = format(Query, sizeof(Query), "SELECT `pMoney` FROM `users` WHERE pName='%s'", CarInfo[i][owner]);

Re: Tag Mismatch - Roberto80 - 30.08.2015

I don't know about SQL,but as i saw,try to change pName= to `pName` =

Re: Tag Mismatch - Sjn - 30.08.2015

Cached variables are not made to use for format. Its used for executing the query (as far as i know). You need to do something like this instead;

PHP код:



new

    Cache:result;


mysql_format(handle, Query, sizeof(Query), "SELECT `pMoney` FROM `users` WHERE pName='%s'", CarInfo[i][owner]);

result = mysql_query(handle, Query, true);