[Ajuda] PHP - Printable Version
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PHP - s4kuL - 12.02.2015
Bom, nгo consigo fazer um sistema para checar se a conta do jogar tem level de administrador maior que 1 para poder logar no painel. Alguйm pode me ajudar com isso? nгo sei nem por onde comeзar.. sou iniciante em PHP.
PHP код:
<!DOCTYPE html>
<html lang="en">
<!-- Mirrored from www.soluslabs.com/clients/clientarea.php by HTTrack Website Copier/3.x [XR&CO'2014], Fri, 09 Jan 2015 20:06:28 GMT -->
<!-- Added by HTTrack -->
<meta http-equiv="content-type" content="text/html;charset=utf-8" />
<!-- /Added by HTTrack -->
<head>
<meta http-equiv="content-type" content="text/html; charset=utf-8" />
<title>GTA:Adrenaline ~ Top Levels</title>
<base />
<script type="text/javascript" src="includes/jscript/jquery.js"></script>
<link href="templates/solusvm-onapp/css/bootstrap.css" rel="stylesheet">
<link href="templates/solusvm-onapp/css/whmcs.css" rel="stylesheet">
<script src="templates/solusvm-onapp/js/whmcs.js"></script>
</head>
<body>
<div style="margin-top:20px"></div>
<div class="logo"><img src="images/logo.png" width="320" height="130" />
</div>
<br />
<div class="navbar navbar-fixed-top">
<div class="navbar-inner">
<div class="container">
<a class="btn btn-navbar" data-toggle="collapse" data-target=".nav-collapse">
<span class="icon-bar"></span>
<span class="icon-bar"></span>
<span class="icon-bar"></span>
</a>
<div class="nav-collapse">
<ul class="nav">
<li>
<a id="pagina-inicial" href="index.php">Inicio</a>
</li>
</ul>
<ul class="nav">
<li>
<a id="pagina-login" href="login.php">Entrar</a>
</li>
</ul>
</div>
<!-- /.nav-collapse -->
</div>
</div>
<!-- /navbar-inner -->
</div>
<!-- /navbar -->
<div class="whmcscontainer">
<div class="contentpadded">
<div class="page-header">
<div class="styled_title">
<h2>Login</h2>
</form>
<script type="text/javascript">
$("#username").focus();
</script>
</div>
</div>
<?php
include('config.php');
session_start();
if(isset($_POST['login']))
{
$nome = mysql_real_escape_string($_POST['nome']);
$query = mysql_query("SELECT * FROM contas WHERE Username = '$nome'", $conectar) or die(mysql_error());
$rows = mysql_num_rows($query);
if($rows)
{
$senha = mysql_real_escape_string($_POST['senha']);
$query = mysql_query("SELECT * FROM contas WHERE Username = '$nome' AND Password = '$senha'", $conectar) or die(mysql_error());
$rows = mysql_num_rows($query);
if($rows)
{
$dados = mysql_fetch_assoc($query);
$nome = $dados['name'];
$_SESSION['username'] = $nome;
header('location: mysql.php');
}
else echo "Senha incorreta.<br>";
}
else
{
echo "Nao ha nenhum usuario registrado com este nome.<br>";
}
}
?>
<form method = "post" action = "">
Nick:<br><input type = "text" name = "nome"><br>
Senha:<br><input type = "password" name = "senha"><br><br>
<input type = "submit" name = "login" value = "Login">
</form>
</div>
<div class="footerdivider">
<div class="fill"></div>
</div>
<div class="whmcscontainer">
<div class="footer">
<div id="copyright">Copyright © 2015 GTA:Adrenaline. Todos os direitos reservados.</div>
<div class="clear"></div>
</div>
</div>
</body>
<!-- Mirrored from www.soluslabs.com/clients/clientarea.php by HTTrack Website Copier/3.x [XR&CO'2014], Fri, 09 Jan 2015 20:06:39 GMT -->
</html>
Re: PHP - smiir - 12.02.2015
1. Na pбgina de login.
PHP код:
<?php
if($dados['row_de_admin']== 1) {
// se for igual a admin
session_start();
$_SESSION["nivel"] = 1;
} else {
// se nгo for
$_SESSION["nivel"] = 0;
}
?>
PHP код:
<?php
require_once("protecao.php");
protegerPagina(1); // 1 = Admin, 0 = Usuбrio
?>
PHP код:
<?php
session_start();
function protegerPainel($value) {
switch($value) {
case 0:
if(isset($_SESSION["nivel"]) == 0)
header("Location: painel-usuario.php");
break;
case 1:
if(isset($_SESSION["nivel"]) == 1)
header("Location: painel-admin.php");
break;
}
}
?>
Re: PHP - Dolby - 12.02.2015
Sua dъvida entгo й referente a MySQL, nгo PHP
.Enfim, vocк jб tem o cуdigo pronto. Fez um select de todo conteъdo da conta do jogador, inclusive fez um fetch para obter o nome do mesmo. Sua dъvida ficou um tanto vaga.
Mysql.php й a pбgina do painel?
Re: PHP - Gii - 12.02.2015
Se fizer desse jeito vai ter problemas:
PHP код:
session_start();
header();