SA-MP Forums Archive
Count words in a string - Printable Version

+- SA-MP Forums Archive (https://sampforum.blast.hk)
+-- Forum: SA-MP Scripting and Plugins (https://sampforum.blast.hk/forumdisplay.php?fid=8)
+--- Forum: Scripting Help (https://sampforum.blast.hk/forumdisplay.php?fid=12)
+--- Thread: Count words in a string (/showthread.php?tid=534043)


[SOLVED] Count words in a string - [XST]O_x - 27.08.2014

Hey I've wondered how it's possible to count how many words are in a string, REGARDLESS of how many spaces are in them.

Something like:
pawn Код:
stock CountWords(string[], &words, &spaces)
{
    ///
}

new wordInt;
new spaceInt;

CountWord("This is a test", wordInt, spaceInt);

printf("\"This is a test\" has %d words and %d spaces", wordInt, spaceInt);
//Would print "This is a test" has 4 words and 3 spaces
I know it's possible with sscanf somehow(or atleast I think), but I just can't get my way around it. Can someone show me how to reach a solution? Or guide me through which functions to use? I'm lost.


EDIT
Solved! Managed to think of something. You may use it if you want.
pawn Код:
stock IsChar(ch)
{
    return ( 'a' <= ch <= 'z' || 'A' <= ch <= 'Z' || '0' <= ch <= '9' );
}

stock FindCharAfterSpace(string[], pos)
{
    new index = pos;
    while((string[index] == ' ' || !IsChar(string[index])) && index < strlen(string)) index++;
    return index;
}

stock FindCharBeforeSpace(string[], pos)
{
    new index = pos;
    while(string[index] == ' ' || !IsChar(string[index])) index--;
    return index;
}

stock CountWords(string[], &words, &spaces)
{
    words = 0;
    spaces = 0;
    
    new wordCount;
    new spaceCount;
    if(IsChar(string[0])) wordCount++;
    for(new i = 0; i < strlen(string); i++) {
        if(string[i] == ' ' || !IsChar(string[i])) {
            if(IsChar(string[FindCharBeforeSpace(string, i)]) && IsChar(string[FindCharAfterSpace(string, i)])) wordCount++, i = FindCharAfterSpace(string, i);
        }
    }
    
    for(new i = 0; i < strlen(string); i++) if(string[i] == ' ') spaceCount++;
    
    words = wordCount;
    spaces = spaceCount;

    printf(" \"%s\" has %d words and %d spaces", string, words, spaces);
}

//Debug test:
public OnFilterScriptInit()
{
    new w = 0, s = 0;
    CountWords("Test 1 2 3    4", w, s);
    CountWords("Test 1 2 3 4", w, s);
    CountWords("Test 1", w, s);
    CountWords("Test", w, s);
    CountWords("Is this some kind   of fuckinG         joke?????? Huh", w, s);
    return 1;
}
pawn Код:
//These printed:
/* "Test 1 2 3    4" has 5 words and 7 spaces
 "Test 1 2 3 4" has 5 words and 4 spaces
 "Test 1" has 2 words and 1 spaces
 "Test" has 1 words and 0 spaces
 "Is this some kind   of fuckinG         joke?????? Huh" has 8 words and 17 spaces*/


Re: Count words in a string - Rudy_ - 27.08.2014

strfind?

Re: Count words in a string - TakeiT - 27.08.2014

use strfind to find spaces, then just do spaces +1 for words :P

Re: Count words in a string - ThePhenix - 27.08.2014

I wrote this, I don't know if its optimized but might work:

PHP код:
stock CountWords(string[], &words, &spaces)
{
    for(new i; string[i]; i++)
    {
        if(string[i] == ' ')
        {
            spaces++;
        }
    }
    words = spaces+1;
} 


Re: Count words in a string - CutX - 27.08.2014

how about this

pawn Код:
count(str[])
{
    new w = 0,i=w;
    while(str[i] == ' ') i++;//skip possible spaces @beginning  
    for(; i < strlen(str); i++)
    {
        if(str[i] == ' ')
        {
            w++;
            while(str[i++] == ' '){}
        }
    }
    return w;
}
adapted it from c++, it will return the number of words regardless what the string might look like.
you could also easily edit this and count the spaces instead of the words.

tested it with this string:
Код:
"  HEY! this is aaaaaaa     test string   "
returned: 6

Re: Count words in a string - [XST]O_x - 27.08.2014

Thanks all. Managed to script my own code eventually.
Might aswell take a look if you're wondering:
pawn Код:
stock IsChar(ch)
{
    return ( 'a' <= ch <= 'z' || 'A' <= ch <= 'Z' || '0' <= ch <= '9' );
}

stock FindCharAfterSpace(string[], pos)
{
    new index = pos;
    while((string[index] == ' ' || !IsChar(string[index])) && index < strlen(string)) index++;
    return index;
}

stock FindCharBeforeSpace(string[], pos)
{
    new index = pos;
    while(string[index] == ' ' || !IsChar(string[index])) index--;
    return index;
}

stock CountWords(string[], &words, &spaces)
{
    words = 0;
    spaces = 0;
    
    new wordCount;
    new spaceCount;
    if(IsChar(string[0])) wordCount++;
    for(new i = 0; i < strlen(string); i++) {
        if(string[i] == ' ' || !IsChar(string[i])) {
            if(IsChar(string[FindCharBeforeSpace(string, i)]) && IsChar(string[FindCharAfterSpace(string, i)])) wordCount++, i = FindCharAfterSpace(string, i);
        }
    }
    
    for(new i = 0; i < strlen(string); i++) if(string[i] == ' ') spaceCount++;
    
    words = wordCount;
    spaces = spaceCount;

    printf(" \"%s\" has %d words and %d spaces", string, words, spaces);
}

//Debug test:
public OnFilterScriptInit()
{
    new w = 0, s = 0;
    CountWords("Test 1 2 3    4", w, s);
    CountWords("Test 1 2 3 4", w, s);
    CountWords("Test 1", w, s);
    CountWords("Test", w, s);
    CountWords("Is this some kind   of fuckinG         joke?????? Huh", w, s);
    return 1;
}
pawn Код:
//These printed:
/* "Test 1 2 3    4" has 5 words and 7 spaces
 "Test 1 2 3 4" has 5 words and 4 spaces
 "Test 1" has 2 words and 1 spaces
 "Test" has 1 words and 0 spaces
 "Is this some kind   of fuckinG         joke?????? Huh" has 8 words and 17 spaces*/


Re: Count words in a string - Rudy_ - 27.08.2014

great and thanks