Errors on "format" - Printable Version

Errors on "format" - Printable Version

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+--- Thread: Errors on "format" (/showthread.php?tid=520786)

Errors on "format" - S4t3K - 20.06.2014

Hi.

I simply used "format" to...format a string, but when compiling, I got these errors :

Код:

date_kilou.pwn(19) : error 012: invalid function call, not a valid address
date_kilou.pwn(19) : error 029: invalid expression, assumed zero
date_kilou.pwn(19) : warning 215: expression has no effect
date_kilou.pwn(19) : error 001: expected token: ";", but found "sizeof"
date_kilou.pwn(19) : fatal error 107: too many error messages on one line

My code is the following :

PHP код:





new string[500] = "";

    new cdate[3], time[3];

    gettime(time[0], time[1], time[2]);

    getdate(cdate[0], cdate[1], cdate[2]);

    for(new i = 0; i < strlen(format); i++)

    {

        

        switch(format[i])

        {

            /*************************

                    Jour

            *************************/

            

            case 'd': format(string, sizeof(string), "%s%02d", string, cdate[2]);

(I try to make a date function, with almost the same features as the php version but in pawn).

I absolutely don't know the source of the errors, so if someone was able to help me, thanks to him in advance.

Re: Errors on "format" - Golf - 20.06.2014

mybe

PHP код:



  case 'd': format(string, sizeof(string), "  '%s' '%02d'  ", string, cdate[2]);

Re : Errors on "format" - S4t3K - 20.06.2014

Already tried, already failed.
This isn't designed to be assigned to a SQL query, so I don't understand the meaning of the simple quotes here.
You'd give me an explaination ?

Re: Errors on "format" - NaClchemistryK - 20.06.2014

Just adding simple " ' " s inside a string won't make any difference.
OT:
It's actually just a simple format. I don't understand the problem of the pawn compilers, they are especially designated to kill someone
And I don't understand why he is expecting a semi colon when you still need several more parameters inside a format.
Maybe try doing simple thing: like putting it in braces, or try simply formatting it with something simple. Like that we might find a way to a solution

Re : Errors on "format" - S4t3K - 20.06.2014

I added the "format" into brackets (which gives me now

PHP код:



case 'd': // line 19

{ // line 20

      format(string, sizeof(string), "%s%02d", string, cdate[2]);  // line 21

} // line 22

And now, the errors are more numerous :

Код:

date_kilou.pwn(21) : error 012: invalid function call, not a valid address
date_kilou.pwn(21) : warning 215: expression has no effect
date_kilou.pwn(21) : warning 215: expression has no effect
date_kilou.pwn(21) : warning 215: expression has no effect
date_kilou.pwn(21) : warning 215: expression has no effect
date_kilou.pwn(21) : warning 215: expression has no effect
date_kilou.pwn(21) : error 001: expected token: ";", but found ")"
date_kilou.pwn(21) : error 029: invalid expression, assumed zero
date_kilou.pwn(21) : fatal error 107: too many error messages on one line

So I tried adding a simple "format" just before, and I get exactly the same errors as above but on the line of the format I added (still line 21) :

PHP код:



case 'd': // line 19

            { // line 20

                format(string, sizeof(string), "%s%s", string, "123"); // line 21

                format(string, sizeof(string), "%s%02d", string, cdate[2]); // line 22

            } // line 23

Re: Errors on "format" - Vince - 20.06.2014

Doesn't it seem obvious that you can't use a function's name as a variable's name?

Re : Errors on "format" - S4t3K - 20.06.2014

@Vince : I renamed "format" to "formatt" and it works absolutely fine.
Thanks.