Player Age Dialog - Printable Version
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+--- Thread: Player Age Dialog (/showthread.php?tid=487621)
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+--- Thread: Player Age Dialog (/showthread.php?tid=487621)
Player Age Dialog - Ryan_Bowe - 14.01.2014
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Re: Player Age Dialog - ikey07 - 14.01.2014
if(strlen(inputtext) < 18 || strlen(inputtext) > 100) return ShowDialog(playerid, 7);
change to
if(strval(inputtext) < 18 || strval(inputtext) > 100) return ShowDialog(playerid, 7);
even more, put new string = strval(inputtext); above that compare and use
if(string < 18 || string > 100) return ShowDialog(playerid, 7);
Re : Player Age Dialog - S4t3K - 14.01.2014
Your format should be like this (idk, i don't use to use mySQL)
PHP код:
format(query, sizeof(query), "UPDATE `playerdata` SET sex = '%d', age = '%d' WHERE username = '%s'", PlayerData[playerid][pSex], string);
(except if you defined it before, in this situation, sorry )
Re: Re : Player Age Dialog - Ryan_Bowe - 14.01.2014
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