String Variables - Printable Version
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String Variables -
MrMou6 - 11.10.2013
Hello, i get a vehicle name from MySQL database:
Код:
mysql_get_field("vName", vInfo[carid][vName]);
(carid is vehicle id)
And use it in:
Код:
format(ma, sizeof(ma), "'%s' ID: %i\n---Antros maљinos nėra---",vInfo[mid1][vName], pInfo[playerid][m1id]);
And in game show me not real name "Infernus", but "i0Cs0".
Maybye someone know why?
P.S. Sorry for my bad english
Re: String Variables -
-=Dar[K]Lord=- - 11.10.2013
pawn Код:
mysql_fetch_field_row(vInfo[carid][vName],"vName");
Try this ...
Re: String Variables -
MrMou6 - 11.10.2013
Quote:
Originally Posted by -=Dar[K]Lord=-
pawn Код:
mysql_fetch_field_row(vInfo[carid][vName],"vName");
Try this ...
|
Nothing...
Re: String Variables -
-=Dar[K]Lord=- - 11.10.2013
well then it isnt saving the car name correctly... You have to get the car name when you store the car name in "vName" and then you have to set it to your variable
Re: String Variables -
MrMou6 - 11.10.2013
Something like this:
Код:
new result[128];
mysql_get_field("vName", result);
vInfo[carid][vName] = result;
?
Then i get this error:
Код:
error 006: must be assigned to an array
Re: String Variables -
xVIP3Rx - 11.10.2013
Can you show where is the vInfo[carid][vName] ? Or add [128] after it..
Re: String Variables -
MrMou6 - 11.10.2013
Yea, i Add [128] when i create vName, and now work. Thanks
Re: String Variables -
DanishHaq - 11.10.2013
pawn Код:
mysql_fetch_field_row(result, "vName");
strmid(vInfo[carid][vName], result, 0, strlen(result));
Edit: If this doesn't work, show me the enumeration for vInfo.