Only excecute the code when atleast 1 row has been found - Printable Version
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Only excecute the code when atleast 1 row has been found -
thimo - 28.07.2013
Hello,
I am busy on mysql and im trying to figure out on how to do it so it only excecutes code when theres atleast 1 row found. This is my code:
pawn Код:
new string[128];
new pname_[MAX_PLAYER_NAME];
GetPlayerName(playerid, pname_, MAX_PLAYER_NAME);
mysql_real_escape_string(pname_, pname_);
format(string, sizeof(string), "SELECT `HouseID` FROM `Houses` WHERE `Houseowner`='%s'", pname_);
mysql_store_result();
if(mysql_retrieve_row)
mysql_function_query( Handle, string, true, "OnPlayerHousesLoad", "d", playerid );
But apparently this is not how you use mysql_retrieve_row but i have no idea on how to do it
Re: Only excecute the code when atleast 1 row has been found -
MP2 - 28.07.2013
mysql_num_rows? You should really use cache.
pawn Код:
new rows, fields;
cache_get_data(rows, fields);
if(rows >= 1)
{
// there is at least 1 row
}
else
{
// No rows
}
Re: Only excecute the code when atleast 1 row has been found -
thimo - 28.07.2013
Thank you!
~Edit: do i not need to use mysql_store_result?