Question about variable - Printable Version
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Question about variable -
FishyZ - 21.07.2013
Quote:
players++;
print(players);
return 1;
}
public OnPlayerDisconnect(playerid, reason)
{
players--;
print(players);
return 1;
}
|
Error :
Quote:
C:\Users\bosi\Desktop\lawl\Scripting 2\gamemodes\HotPursuit.pwn(337) : error 035: argument type mismatch (argument 1)
C:\Users\bosi\Desktop\lawl\Scripting 2\gamemodes\HotPursuit.pwn(344) : error 035: argument type mismatch (argument 1)
Pawn compiler 3.2.3664 Copyright © 1997-2006, ITB CompuPhase
2 Errors.
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Re: Question about variable -
FishyZ - 21.07.2013
Help please
Re: Question about variable -
Th3_P4dr1n0 - 21.07.2013
You missing "" in print.
print("players"); or printf("%d", players);
Re: Question about variable -
Scenario - 21.07.2013
Read the mutha' fuckin' forum rules before posting.
http://forum.sa-mp.com/announcement.php?f=12
Now, had you of done a little research, you would of realized that the "
print" function only handles strings. Since "players" is an integer and not a string, you cannot call print(players). However, you can use
printf to format a string and print the value of the integer. The poster above me gave you an example of printf already.
Re: Question about variable -
FishyZ - 21.07.2013
Quote:
Originally Posted by Th3_P4dr1n0
You missing "" in print.
print("players"); or printf("%d", players);
|
Thanks!
Now I am getting another error
Quote:
C:\Users\bosi\Desktop\lawl\Scripting 2\gamemodes\HotPursuit.pwn(7) : fatal error 100: cannot read from file: "zcmd"
|
My zmcd fail is here.
Quote:
C:\Users\bosi\Desktop\lawl\Scripting 2\include
|
And should I write #include <zcmd> or #include <zcmd.inc>
Re: Question about variable -
Scenario - 21.07.2013
Search and you'll find your answer.