Creating array with size declared in variable

Creating array with size declared in variable - Printable Version

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+--- Thread: Creating array with size declared in variable (/showthread.php?tid=434921)

Creating array with size declared in variable - GiS - 04.05.2013

Hey,

I know it's possible, what am I doing wrong here:

pawn Код:

new size = 5,
    arr[size];
// error 008: must be a constant expression; assumed zero

Re: Creating array with size declared in variable - RajatPawar - 04.05.2013

EDIT: My bad.

AW: Creating array with size declared in variable - Nero_3D - 04.05.2013

The expression must be constant

pawn Код:

const size = 5;
new array[size];

Re: Creating array with size declared in variable - GiS - 04.05.2013

Nope, that's not the solution. Same errors given.

Quote:

Originally Posted by Nero_3D

The expression must be constant

pawn Код:

const size = 5;
new array[size];

Works, thanks.

But different attempt now:

pawn Код:

const size = getConstant(); // Returns any positive integer
new array[size];

This does not work.

AW: Creating array with size declared in variable - Nero_3D - 04.05.2013

Sure it doesn't, if you want to achieve something like an dynamic array than I will disappoint you that's not possible

Re: Creating array with size declared in variable - Pottus - 04.05.2013

Use #define MY_ARRAY_SIZE 5
then new array[MY_ARRAY_SIZE];

Re: AW: Creating array with size declared in variable - GiS - 04.05.2013

Quote:

Originally Posted by Nero_3D

Sure it doesn't, if you want to achieve something like an dynamic array than I will disappoint you that's not possible

A dynamic array would be a vector, however, that's not what I am trying to achieve. I am trying to get the size for the array I need and then create this array with the required size.

Quote:

Originally Posted by [uL]Pottus

Use #define MY_ARRAY_SIZE 5
then new array[MY_ARRAY_SIZE];

That won't solve the problem as I cannot define the returned integer of a function.

Re: Creating array with size declared in variable - Pottus - 04.05.2013

You can't use dynamic arrays I thought that was mentioned already? You can't define an array some arbitrary size it must be a constant when compiling. What you could do is make your array larger than what you need and use your function to define the upper bound. There is one other option that is probably less than ideal https://sampforum.blast.hk/showthread.php?tid=58827

Re: Creating array with size declared in variable - RajatPawar - 04.05.2013

You can do somethings with 'new' and 'delete' operators, defining them as constants, then putting it as the size, then checking with code IF it's an okay size, if not, deleting it and redefining it, and so on.