#if directive problem - Printable Version

#if directive problem - Printable Version

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+--- Thread: #if directive problem (/showthread.php?tid=422333)

#if directive problem - RajatPawar - 13.03.2013

I have got this code:

pawn Код:

#define fX InfoBox[boxid][iX];
    #define fY InfoBox[boxid][iY];
    #if fX - fY > 71
    #error BlaBla
    #endif

So, it gives me the "constant" error.
Is there any way I can do this? I know the defination has to be constant, but I tried making it in different ways without any results.
It would be awesome if someone could help!

Re: #if directive problem - Vince - 13.03.2013

Didn't you ask a similar question just a few days ago? The compiler cannot calculate the values of fX and fY because they are runtime variables. They are initialized only when the script is run. I recommend you use assert(); this evaluates the expression at runtime and will exit the server with runtime error 1 if the expression evaluates to false.

Re: #if directive problem - RajatPawar - 13.03.2013

Quote:

Originally Posted by Vince

Didn't you ask a similar question just a few days ago? The compiler cannot calculate the values of fX and fY because they are runtime variables. They are initialized only when the script is run. I recommend you use assert(); this evaluates the expression at runtime and will exit the server with runtime error 1 if the expression evaluates to false.

Oh yes, I did, but this is a different one (not quite, actually)
Anyways, I tried what you said:

pawn Код:

new fX = InfoBox[boxid][iX];
    new fY = InfoBox[boxid][iY];
    new s = fX - fY;    
    #assert s < 71

Gives me an error even if I equated fX = 240 and fY = 220.

Re: #if directive problem - Vince - 13.03.2013

I said assert() as in statement, not #assert as a directive.

Re: #if directive problem - RajatPawar - 13.03.2013

Quote:

Originally Posted by ******

Just use "if" instead of "#if" (and don't use "assert").

Nah, wanted to give a compiler error or run time error.. I'll check out assert();

Re: #if directive problem - LarzI - 13.03.2013

Compiler error is impossible if the value is set after compiling, obviously. This is why it won't work with #if #error #endif. The assert function is a "solution", although I don't see why you don't just use normal prints instead to "simulate" an error, as assert won't tell you anything else but "Assertion failed".

Re: #if directive problem - RajatPawar - 13.03.2013

Well, since there's no other option.. Basically, it's this textdraw string I don't want a scripter to exceed by 33 characters which I need to check. I tried inserting the newline character after the 33rd character, but it messed up the if the scripter had used it before the 33rd character. I guess I'll use a loop like:

pawn Код:

for ( new i; .. ) { if(strfind ( string.. '~' && ch[i+1] == n && ch [i+2] == '~') break, else strins ( deststr, ''~n~'', 33)

It's a typing problem here, so try to understand what I am conveying ! This should work, yes?

Re: #if directive problem - RajatPawar - 13.03.2013

No, that would in a way defeat the purpose of my FS ! It's a textdraw menu FS, so menu options can vary from '1. Buy happiness' to '1. Buy prosperity along with happiness.' !

Re: #if directive problem - RajatPawar - 13.03.2013

Okay ! This is what I am gonna do:

pawn Код:

function CreateMyInfoBox(string[])
{
    .. 
}
function ShowInfoBoxToPlayer ( playerid, box )
{
      if(strfind( box_enum[box][boxstring], "~n~" )  > 33 )
      {
          strins( box_enum[box][boxstring], "~n~", 30 );
       }
}

So you are saying I could do something like this?