Get Rotation X according angle player? - Printable Version
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+--- Thread: Get Rotation X according angle player? (/showthread.php?tid=417296)
Get Rotation X according angle player? - HitnKill - 20.02.2013
Hi i want to get the Rotation X for a object according the player angle, but i dont know how to do this calculation, its possible?
Re: Get Rotation X according angle player? - Babul - 20.02.2013
the asin() and acos() functions will give you the results you need. besides the angle, you also need a radius. if you set the radius to 1.0, then the X-and Y-results will ne normalized.
Re : Get Rotation X according angle player? - HitnKill - 20.02.2013
I tried but he dont work.
PHP код:
Angle= new Float:Angle;
GetPlayerFacingAngle(playerid, Angle);
X to point = -1412.1890
Y to point = 2351.3638
My calcul = -1412.1890 * acos(Angle) - 2351.3638 * asin(Angle)
Re : Get Rotation X according angle player? - HitnKill - 20.02.2013
https://sampforum.blast.hk/showthread.php?tid=219539
PHP код:
Float:PointAngle(playerid, Float:xa, Float:ya, Float:xb, Float:yb)
{
new Float:carangle;
new Float:xc, Float:yc;
new Float:angle;
xc = floatabs(floatsub(xa,xb));
yc = floatabs(floatsub(ya,yb));
if (yc == 0.0 || xc == 0.0)
{
if(yc == 0 && xc > 0) angle = 0.0;
else if(yc == 0 && xc < 0) angle = 180.0;
else if(yc > 0 && xc == 0) angle = 90.0;
else if(yc < 0 && xc == 0) angle = 270.0;
else if(yc == 0 && xc == 0) angle = 0.0;
}
else
{
angle = atan(xc/yc);
if(xb > xa && yb <= ya) angle += 90.0;
else if(xb <= xa && yb < ya) angle = floatsub(90.0, angle);
else if(xb < xa && yb >= ya) angle -= 90.0;
else if(xb >= xa && yb > ya) angle = floatsub(270.0, angle);
}
GetVehicleZAngle(GetPlayerVehicleID(playerid), carangle);
return floatadd(angle, -carangle);
}