Get all ids of connected players? - Printable Version
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+--- Thread: Get all ids of connected players? (
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Get all ids of connected players? -
Azazelo - 31.10.2012
Best(fastest) way to get id of all player connected in game?
Quote:
stock ConnectedPlayersIDs()
{
new a = MAX_PLAYERS,counter;
do
{
if(IsPlayerConnected(counter)) ; // best way to store
counter++;
}
while(a<=counter);
return ;// what array ![Huh?](images/smilies/confused.gif)
}
|
AW: Get all ids of connected players? -
Skimmer - 31.10.2012
Add this top of the script
pawn Код:
new PlayerID[MAX_PLAYERS];
pawn Код:
stock ConnectedPlayersIDs()
{
for(new i = 0; i < MAX_PLAYERS; i++)
{
if(IsPlayerConnected(i))
{
PlayerID[i] = i;
}
}
return 1;
}
You can use
PlayerID[playerid] to get anyones ID
Re: Get all ids of connected players? -
Azazelo - 31.10.2012
Thank and when i search for players in game i do same loop
![Huh?](images/smilies/confused.gif)
And if for example PlayerID 5 not used but 6 7 8 used i got ther is PlayerID[5] = 6
Right
Re: Get all ids of connected players? -
Jefff - 31.10.2012
pawn Код:
new ConnectedID[MAX_PLAYERS];
stock ConnectedPlayersIDs()
{
new Counter;
for(new i,g = GetMaxPlayers(); i < g; i++)
if(IsPlayerConnected(i))
ConnectedID[Counter++] = i;
return Counter;
}
AW: Get all ids of connected players? -
Skimmer - 31.10.2012
My question, why are you using this stock ?
Create always the
for-loop. Here's an example.
I'll give everyone $500 cash!
pawn Код:
for(new i = 0; i < MAX_PLAYERS; i++)
{
if(IsPlayerConnected(i))
{
GivePlayerMoney(i, 500);
SendClientMessage(i, -1, "An Admin has sent you $500.");
}
}
So, i use
i instead of
playerid
Re: Get all ids of connected players? -
iggy1 - 31.10.2012
The best, easiest and fastest would be using foreach.
pawn Код:
foreach(new playerid, Player)
{
//this loops through only connected players
//either store in an array like above or just use "playerid" (or any other identifier you choose)
}
Like the comment says it will only loop through connected players never more.
Re: Get all ids of connected players? -
Azazelo - 31.10.2012
Thank you all for help.