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Another SQL Problem... - Printable Version

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Another SQL Problem... - aRoach - 03.04.2012

Well guys, I need some help about this:
pawn Код:
new Query[ 129 ];
format( Query, 129, "INSERT INTO `Banlist` VALUES('%s','%s','%s','%s','%s')", GetPlayerIpEx( u_P ), pName( u_P ), s_R, pName( playerid ), Date( ) );
db_query( g_dbKeptAlive, Query );
It doesn't put the information in the DB...

-----------

I've tried this too:
pawn Код:
new Query[ 129 ];
format( Query, 129, "INSERT INTO Banlist(`IP`, `Name`, `Reason`, `Admin`, `BanDate`) VALUES('%s', '%s', '%s', '%s', '%s')", GetPlayerIpEx( u_P ), pName( u_P ), s_R, pName( playerid ), Date( ) );
db_query( g_dbKeptAlive, Query );
-----------

So, please.. Help me!


Re: Another SQL Problem... - blank. - 03.04.2012

In the debug output, does the query cut out?


Re: Another SQL Problem... - aRoach - 03.04.2012

The same thing, when I try to do It in the SQL Manager with some random Values it Works...


Re: Another SQL Problem... - [MG]Dimi - 03.04.2012

pawn Код:
new Query[ 129 ];
format( Query, 129, "INSERT INTO `Banlist` (`IP`, `Name`, `Reason`, `Admin`, `BanDate`) VALUES ('%s', '%s', '%s', '%s', '%s')", GetPlayerIpEx( u_P ), pName( u_P ), s_R, pName( playerid ), Date( ) );
db_query( g_dbKeptAlive, Query );
Column and Table name inside `` and values inside ' '. When using INSERT INTO you must define Columns in which to store values before giving values.


Re: Another SQL Problem... - aRoach - 03.04.2012

The same thing, I've used this first but... no result..


Re: Another SQL Problem... - Edvin - 03.04.2012

probably is the dialogid ... other function works on it?


Re: Another SQL Problem... - aRoach - 03.04.2012

The dialog works fine lol...
And yes, the other functions works fine...


Re: Another SQL Problem... - blank. - 03.04.2012

Quote:
Originally Posted by [MG]Dimi
Посмотреть сообщение
pawn Код:
new Query[ 129 ];
format( Query, 129, "INSERT INTO `Banlist` (`IP`, `Name`, `Reason`, `Admin`, `BanDate`) VALUES ('%s', '%s', '%s', '%s', '%s')", GetPlayerIpEx( u_P ), pName( u_P ), s_R, pName( playerid ), Date( ) );
db_query( g_dbKeptAlive, Query );
Column and Table name inside `` and values inside ' '. When using INSERT INTO you must define Columns in which to store values before giving values.
That doesn't make any difference,
OP, does the query cut out on debug output?


Re: Another SQL Problem... - Edvin - 03.04.2012

Oh, i got it xD

Try to increase the new Query ... in:
Код:
new Query[ 256 ];
Try now ^^, shut work now


Re: Another SQL Problem... - [MG]Dimi - 03.04.2012

Quote:
Originally Posted by blank.
Посмотреть сообщение
That doesn't make any difference,
OP, does the query cut out on debug output?
Trust me that it does since 90% of time MySQL (or SQLLite) return Error in SQL Synatx.