Problem with split - Printable Version

Problem with split - Printable Version

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Problem with split - [IL]HeHu - 12.07.2011

Hey, this is the split function to those unfamiliar with it:

PHP код:



public split(const strsrc[], strdest[][], delimiter)

{

    new i, li;

    new aNum;

    new len;

    while(i <= strlen(strsrc)){

        if(strsrc[i]==delimiter || i==strlen(strsrc)){

            len = strmid(strdest[aNum], strsrc, li, i, 128);

            strdest[aNum][len] = 0;

            li = i+1;

            aNum++;

        }

        i++;

    }

    return 1;

}

Now I tried to do this:

PHP код:



        new Parts[3][52];

            split(mysql_Float(SQL_USERS,PlayerInfo[playerid][pUID],"spawn"), Parts, ',');

And this is the error it puts out:

PHP код:



C:\Users\Mark\Desktop\GRP.pwn(350) : error 035: argument type mismatch (argument 1)

Pawn compiler 3.2.3664              Copyright (c) 1997-2006, ITB CompuPhase



1 Error.

Re: Problem with split - [IL]HeHu - 12.07.2011

Cause I am not quite comfortable with using sscanf, I don't know why really. I'll try and look through it again though, thanks.

Re: Problem with split - [IL]HeHu - 12.07.2011

Did it with sscanf:

PHP код:



            sscanf(mysql_Int(SQL_USERS,PlayerInfo[playerid][pUID],"spawn"),"p<,>fff", PlayerInfo[playerid][pSpawn][0], PlayerInfo[playerid][pSpawn][1],PlayerInfo[playerid][pSpawn][2]);

Still writes the same error, here is mysql_Int:

PHP код:



stock mysql_Get(table[],id,key[])
{
    new string[128];
    format(string, sizeof(string), "SELECT `%s` FROM `%s` WHERE `id` = '%d'",key,table,id);
    mysql_query(string);
        mysql_store_result();
        mysql_fetch_row_format(string);
    return string;
}

mysql_int is just calling mysql_Get and converting it into integers.