[Question]Define in define - Printable Version

[Question]Define in define - Printable Version

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+---- Thread: [Question]Define in define (/showthread.php?tid=265384)

[Question]Define in define - Scottas - 30.06.2011

There are any way to use defines in define? For example:

pawn Код:

#define one       #if !defined two #error...

So in that way, I could check entered parameters doesn't dublicated for some setup functions during compile time. Or there are any other way to do this?

Re: [Question]Define in define - Shadoww5 - 01.07.2011

Could you explain again ?

Re: [Question]Define in define - Lilcuete - 01.07.2011

I think he's trying to say that if he can put 2 defines in 1 but i think thats not possible.

Re: [Question]Define in define - [LoD]Hauke - 01.07.2011

Maybe you mean

pawn Код:

#if defined one && !defined two
    #define xyz
#endif

pawn Код:

#if defined two
    #define one
#endif

Re: [Question]Define in define - Shadoww5 - 01.07.2011

From what I understood it would be like this:

PHP код:



#if defined one
    #define two
#else
    #define one
#endif

Re: [Question]Define in define - BigETI - 01.07.2011

Quote:

Originally Posted by Scottas

There are any way to use defines in define? For example:

pawn Код:

#define one       #if !defined two #error...

So in that way, I could check entered parameters doesn't dublicated for some setup functions during compile time. Or there are any other way to do this?

Yes it is

Examples:

pawn Код:

#define RED 0xFF0000FF
#define invalidid SendClientMessage(playerid, RED, "This Player ID is not connected.");

pawn Код:

#define SetVehicleNumberPlateF(%0,%1,%2); UseBrackets\
    {\
    new formatstring[32];\
    format(formatstring,sizeof(formatstring),%1,%2);\
    SetVehicleNumberPlate(%0,formatstring);\
    }

#define UseBrackets if(negative != positive)
new bool:negative = false, bool:positive = true;

As you can see that I've used defines inside the defines.
But if you write the same define text into it's own define so the compiler will crash.

Example:

pawn Код:

#define fail_defined_variable fail_defined_variable //It loops around and there is no end
new fail_defined_variable;

In the worst case after compiling it you have to close pawncc.exe from taskmanager.

Re: [Question]Define in define - Scottas - 01.07.2011

Well, I'll give a better example

pawn Код:

// Some kind of function:
#define AddSymbol(%0)

// Then use this function
AddSymbol(SYMBOL_ONE);
AddSymbol(SYMBOL_TWO);
AddSymbol(SYMBOL_THREE);

What I am trying to do, is to make that compiler would give an error, if you enter the same symbol twice, like:

pawn Код:

// Then use this function
AddSymbol(SYMBOL_ONE);
AddSymbol(SYMBOL_TWO);
AddSymbol(SYMBOL_THREE);
AddSymbol(SYMBOL_TWO);

In this case, function AddSymboll should contain something like:

pawn Код:

#define AddSymbol(%0) #if defined SYMBOL_%0 #error Symbol already exists #endif

But function like that wont compile, it gives error. So all I want to know, is it possible to make something like that?

AW: Re: [Question]Define in define - Nero_3D - 01.07.2011

Just use a stock

pawn Код:

#define AddSymbol(%0) stock %0

AddSymbol(SYMBOL_ONE);
AddSymbol(SYMBOL_TWO);
AddSymbol(SYMBOL_THREE);
AddSymbol(SYMBOL_TWO);

Re: [Question]Define in define - Scottas - 02.07.2011

I am trying to add a field into sqlite database, and instead of getting table info and checking if field already exists, I want make something what I've tried to explane.

Nero, thanks. I haven't thought about this.