This is possible? - Printable Version

This is possible? - Printable Version

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This is possible? - Baboon - 29.03.2011

Код:

for(new i = 0; i < MAX_PLAYERS; i++)
{
	if(IsPlayerConnected(i))
	{
		for(new a = 0; a < MAX_PLAYERS; a != i; a++)
		{
			if(IsPlayerConnecteD(a))
			{
			}
		}
	}
{

Re: This is possible? - Hornet600 - 29.03.2011

why loop two times MAX_PLAYERS?? seems weird ...if you explain more what you want to do...

AW: This is possible? - Nero_3D - 29.03.2011

actually I cant see the reason for nested player loops but its possible
Just get foreach, it uses an advanced structure to create a faster loops

Re: This is possible? - Baboon - 01.04.2011

okay, because I want to use variables in it for my scoreboard in the end of the session, like who has the most kills etc. But is there a way to ingnore if a and i are the same?

AW: Re: This is possible? - Nero_3D - 01.04.2011

Quote:

Originally Posted by timothyinthehouse

okay, because I want to use variables in it for my scoreboard in the end of the session, like who has the most kills etc. But is there a way to ingnore if a and i are the same?

pawn Код:

(a < MAX_PLAYERS) && (a != i)

But there are better sorting methodes than two player loops

That would be Insertionsort, just ****** Sorting algorithm for more advanced once
Some advanced sorthing algorithm like quicksort can be found in this forum

pawn Код:

new
    i,
    j,
    id,
    value,
    id[sizeof Kills] = {0, 1, 2, ...};
for( ; i != sizeof Kills; ++i) {
    value = Kills[i];
    for(j = i; (j != 0) && (Kills[id[j - 1]] < value); --j) {
        id[j] = id[j - 1]
    }
    id[j] = i;
}
//id[0] is the id with the most kills (Kills[id[0]] would be the kills)