#define, #else,#endif - Printable Version

#define, #else,#endif - Printable Version

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+---- Thread: #define, #else,#endif (/showthread.php?tid=184402)

#define, #else,#endif - Jefff - 19.10.2010

Can someone explain me why this not works?
top

pawn Код:

new array=1;

init
SetTimer

pawn Код:

public Show()
{
    if(array)
    {
        #if !defined SOMETHING
            #define SOMETHING
        #endif
        print("Defined");
    }else{
        #if defined SOMETHING
            #undef SOMETHING
        #endif
        print("Undefined");
    }
    #if defined SOMETHING
    print("Defined :D");
    #else
    print("Not defined :D");
    #endif
    return 1;
}

Shows
Defined
Not defined

Defined
Not defined

...

Re: #define, #else,#endif - Cameltoe - 19.10.2010

Pretty self explained the way i see it.

new array;
new array = 1;
__________________________________

1. Checks if SOMETHING is defined.
2. defines if SOMETHING isn't defined
3. Prints "Defined"
4. Checks if SOMETHING is defined.
5. undefines SOMETHING if it's defined.
6. prints "Undefined"

Re: #define, #else,#endif - Gh0sT_ - 19.10.2010

#define text (1)
than
#if text (1) (or 0) .. your func #endif

Re: #define, #else,#endif - Jefff - 19.10.2010

Quote:

Originally Posted by Gh0sT_

#define text (1)
than
#if text (1) (or 0) .. your func #endif

So i've undefined symbol SOMETHING

this #define SOMETHING 1 must be on top not in ;x

>>> HELP <<<

Re: #define, #else,#endif - Slice - 19.10.2010

https://sampforum.blast.hk/showthread.php?tid=166680

Re: #define, #else,#endif - Jefff - 19.10.2010

Quote:

Originally Posted by g_aSlice

https://sampforum.blast.hk/showthread.php?tid=166680

Nothing usefull

Re: #define, #else,#endif - Jefff - 20.10.2010

ok none knows, so delete please this topic and thx for none help

Re: #define, #else,#endif - Agent* - 20.10.2010

You are using the syntax on a wrong way, on a very suspicious wrong way -_-
You first check if it SOMETHING is defined, if it is NOT defined, you define it, than you check if SOMETHING is defined, if it is defined, you undefine it. You are repeating the syntax/function all the time which causes the prints. On a easier way to explain it to you, I will make it in steps:

1. You check if SOMETHING is not defined
2. If it is not defined, you define it
3. Then below it checks if SOMETHING is defined, if it is, than you undefine it
4. The syntax (#if !defines SOMETHING) on the top cheks if it is not defined
5. The last check undefined it, but the syntax on the top checks if it is not defined, if it is not, it defines again.

Sorry if it is quite difficult, I couldn't explain it on an easier way. In a line: The function/syntax you made is an endless process

Re: #define, #else,#endif - Jefff - 20.10.2010

I know what am doing ;x i am not a noob.
i run forst time timer so array == 1 and

pawn Код:

#if !defined SOMETHING
            #define SOMETHING
        #endif

SOMETHING is NOT defined so I #define and next is

pawn Код:

#if defined SOMETHING
    print("Defined :D");
    #else
    print("Not defined :D");
    #endif

yes i define so must print

pawn Код:

Define
Defined :D

but prints

pawn Код:

Defined
Not Defined :D

why this works only here

pawn Код:

if(array)
    {
        #if !defined SOMETHING
            #define SOMETHING
        #endif
        print("Defined");
    }

but not here

pawn Код:

#if defined SOMETHING
    print("Defined :D");
    #else
    print("Not defined :D");
    #endif

too

Re: #define, #else,#endif - MadeMan - 20.10.2010

It doesn't matter what code you have between lines with #.

When compiling, your code actually looks like this:

pawn Код:

#if !defined SOMETHING
            #define SOMETHING
        #endif

        #if defined SOMETHING
            #undef SOMETHING
        #endif

    #if defined SOMETHING
    print("Defined :D");
    #else
    print("Not defined :D");
    #endif

So it will #undef SOMETHING anyway, because it comes after #define.

Re: #define, #else,#endif - Jefff - 20.10.2010

OMG so great

pawn Код:

public Show()
{
    if(array)
    {
        #if !defined SOMETHING
            #define SOMETHING
            print("Defined");
        #endif
    }else{
        #if defined SOMETHING
            #undef SOMETHING
            print("Undefined");
        #endif
    }
    #if defined SOMETHING
    print("Defined :D");
    #else
    print("Not defined :D");
    #endif
    return 1;
}

then why not prints
Defined
Undefined
Not defined

Re: #define, #else,#endif - LarzI - 20.10.2010

Because the message "Undefined" only get's printed of array is equal to 0 (or false).

If you try to remove

pawn Код:

#if defined SOMETHING
            #undef SOMETHING
            print("Undefined");
        #endif

you'll probably notice that it will print "Defined

" instead of "Not defined

Re: #define, #else,#endif - Jefff - 20.10.2010

Lol very very... stupid, ok thx 4 explaining, solved