Problem with mysql phone number - Printable Version
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Problem with mysql phone number -
vection - 07.10.2010
I trying to do that if someone would buy a phone number. if someone already got it its will take somthing else.
pawn Код:
new randphone = 100000 + random(899999);
new Query[200];
format(Query, sizeof(Query), "SELECT * FROM `playerinfo` WHERE `phonenr` = '%d'", randphone);
mysql_query(Query);
if( IF HE DIDNT GOT IT )
PlayerInfo[playerid][pPnumber] = randphone;
Re: Problem with mysql phone number -
vection - 08.10.2010
UPPPPpppppppppppp
Re: Problem with mysql phone number -
LarzI - 08.10.2010
pawn Код:
RANDPHONE: //creating a point where you can go back to
randphone = 100000 + random(899999);
new Query[200];
format(Query, sizeof(Query), "SELECT * FROM `playerinfo` WHERE `phonenr` = '%d'", randphone);
mysql_query(Query);
foreach(Player, i) //use a normal for loop if you don't have for each (i < MAX_PLAYERS)
{
if( randphone == PlayerInfo[i][pPnumber] )
goto RANDPHONE; //goes back to that point we made earlier
else
PlayerInfo[playerid][pPnumber] = randphone;
}
The best way I can think of..
Re: Problem with mysql phone number -
vection - 08.10.2010
This code doesnt work. when i writing a new phone that already have some player (Which his not connected) its changed it.
Re: Problem with mysql phone number -
Tommie1331 - 08.10.2010
replace random(899999); with random(%d)
i think its like that ill check on my server layer as your offline as im trying to scrt a couple of mini misions