Wondering about something, just out of curiosity.

Wondering about something, just out of curiosity. - Printable Version

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Wondering about something, just out of curiosity. - Hiddos - 17.09.2010

So I figured out it was possible to insert "defined" values into string parameters like this:

pawn Code:

#define cowstring "Cows are over "
#define cowamount 9000

print(#cowstring #cowamount "!!!!!");

Note that this'll print "Cows are over 9000!!!!!".

Now my burning question is: Is it possible to use exactly the same method, but then with simple variables?"

Re: Wondering about something, just out of curiosity. - Hiddos - 18.09.2010

That's a bump hehe, guess it's allowed now.

I also wondered about something different: When should I use "new" variables and when should I use "static" ones?

I already had this timer idea:

pawn Code:

new timertimer;
public OnRoundStart()
{
  timertimer = SetTimer("Timer", 1000, 1);
}

forward Timer();
public Timer()
{
  static seconds, minutes = 10;
  if(seconds == 0 && minutes == 0)
  {
    OnRoundEnd();
    minutes = 10;
    KillTimer(timertimer);
    return;
  }
  if(seconds == 0) { seconds = 60; minutes--; }
  seconds--;
  new string[6];
  if(seconds < 10) format(string, sizeof string, "%d:0%d", minutes, seconds);
  else format(string, sizeof string, "%d:%d", minutes, seconds);
  TextDrawSetString(TimerTXT, string);
}

But now I'm just wondering if this is correct usage for it or not ^^

Re: Wondering about something, just out of curiosity. - Kyosaur - 18.09.2010

Quote:

Originally Posted by Hiddos

That's a bump hehe, guess it's allowed now.

I also wondered about something different: When should I use "new" variables and when should I use "static" ones?

I already had this timer idea:

pawn Code:

//stuff

But now I'm just wondering if this is correct usage for it or not ^^

Well it really depends on what your variable stores. The difference between "new" and "static" is that static retains its value when used in a function. When the function ends, the variables value is still existent. So if you have:

Code:

static test = 5;
test++;

in a function, and you call that function 3 times, your results will be 8 instead of it being 6.

EDIT:

Oh yeah, when you assign a value to the static variable while initializing it, that assignment only happens that one time :P.

As for your first post: No. The stringize operator is very literal, if you do something like #var it will add "var" into the string, instead of the value.

Re: Wondering about something, just out of curiosity. - Hiddos - 18.09.2010

Quote:

Originally Posted by Kyosaur

Code:

static test = 5;
test++;

in a function, and you call that function 3 times, your results will be 8 instead of it being 6.

Ah thanks for explaining, now I fully got that part ^^. But any idea about the macro/define question?

Re: Wondering about something, just out of curiosity. - Kyosaur - 18.09.2010

Quote:

Originally Posted by Hiddos

Ah thanks for explaining, now I fully got that part ^^. But any idea about the macro/define question?

Yeah i edited my post with an answer for that as well :P.