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How to transform 01012010 style dates to normal? - Printable Version

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+---- Thread: How to transform 01012010 style dates to normal? (/showthread.php?tid=142574)



How to transform 01012010 style dates to normal? - un4seen - 18.04.2010

Hi. I have dates in format 01012010 ([day][month][year]).
It's with leading zeros. I want to get day, month, year from this. (ex. day = 1, month = 1, year = 2010)

It will be something like UncodeDate(datecode, &day, &month, &year); but I don't know how to wrote this.

Thanks.


Re: How to transform 01012010 style dates to normal? - .(Infinite Imagination). - 18.04.2010

you need this?

Код:
stock GetDMY(&day, &month, &year)
{
	new d, m, y;
	getdate(y, m, d);
	day = d;
	month = m;
	year = y;
	return 1;
}



Re: How to transform 01012010 style dates to normal? - Kyosaur - 19.04.2010

Quote:
Originally Posted by © ŦĥЗ ǺĽẽẌṖŎịŚỘń
you need this?

Код:
stock GetDMY(&day, &month, &year)
{
	new d, m, y;
	getdate(y, m, d);
	day = d;
	month = m;
	year = y;
	return 1;
}
What a dumb function lol, all you basically did was rename getdate to GetDMY.


Re: How to transform 01012010 style dates to normal? - cloud9 - 19.04.2010

Quote:
Originally Posted by © ŦĥЗ ǺĽẽẌṖŎịŚỘń
you need this?

Код:
stock GetDMY(&day, &month, &year)
{
	new d, m, y;
	getdate(y, m, d);
	day = d;
	month = m;
	year = y;
	return 1;
}
lmao

pawn Код:
//well anyways here is it, not tested

//lets say you have stored the value in a string called "Date"
new Date[2],Month[2],Year[2];
strmid(Day, Date, 0, 1);
strmid(Day, Month, 2, 3);
strmid(Day, Year, 4, 7);



Re: How to transform 01012010 style dates to normal? - un4seen - 22.04.2010

A refresh!


Re: How to transform 01012010 style dates to normal? - ziomal432 - 22.04.2010

Код:
GetDMY(&day, &month, &year)
{
getdate(year, month, day);
}